m(x^2+1+2x)+4x=0

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Solution for m(x^2+1+2x)+4x=0 equation:


Simplifying
m(x2 + 1 + 2x) + 4x = 0

Reorder the terms:
m(1 + 2x + x2) + 4x = 0
(1 * m + 2x * m + x2 * m) + 4x = 0
(1m + 2mx + mx2) + 4x = 0

Solving
1m + 2mx + mx2 + 4x = 0

Solving for variable 'm'.

Move all terms containing m to the left, all other terms to the right.

Add '-4x' to each side of the equation.
1m + 2mx + mx2 + 4x + -4x = 0 + -4x

Combine like terms: 4x + -4x = 0
1m + 2mx + mx2 + 0 = 0 + -4x
1m + 2mx + mx2 = 0 + -4x
Remove the zero:
1m + 2mx + mx2 = -4x

Combine like terms: -4x + 4x = 0
1m + 2mx + mx2 + 4x = 0

The solution to this equation could not be determined.

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